ElectoralMap.org
Plant your flag
Presidential election · 1836

1836 electoral map

Martin Van Buren (Democratic) won the 1836 presidential election with 167 electoral votes to William Henry Harrison's 73. Buren carried 15 of the 26 states that took part.
Winner
Martin Van Buren
167
Whig
William Henry Harrison
73
Hugh Lawson White 26Daniel Webster 14Willie P. Mangum 11
official Electoral College count
AL7AKAZAR3CACOFLGA11HIIDIL5IN9IAKSKY15LA5ME10MI3MNMS4MO4MTNENVNMNY42NC15NDOH21OKORPA30SC11SDTN15TXUTVA23WAWVWIWYVT 7NH 7MA 14RI 4CT 8NJ 8DE 3MD 10DC
DemocraticWhigNot a state yet / did not vote
18321840
Good to know
  • The Whigs ran four regional candidates instead of one; the map shows their states together as Whig.

States won in 1836

Martin Van Buren· Democratic
15 states
New York 42Pennsylvania 30Virginia 23North Carolina 15Maine 10Connecticut 8Alabama 7New Hampshire 7Illinois 5Louisiana 5Mississippi 4Missouri 4Rhode Island 4Arkansas 3Michigan 3
William Henry Harrison· Whig
11 states
Ohio 21Kentucky 15Tennessee 15Massachusetts 14Georgia 11South Carolina 11Maryland 10Indiana 9New Jersey 8Vermont 7Delaware 3

Electoral College in 1836

26 states held 294 electoral votes in 1836. The largest prize was New York with 42 electoral votes.

Compare with every other election, see electoral votes by state today, or draw your own 2028 map.

Sources: Wikipedia (CC BY-SA 4.0): results by state, electors by state and year, and the 1836 election article.