Presidential election · 1988
1988 electoral map
George H. W. Bush (Republican) won the 1988 presidential election with 426 electoral votes to Michael Dukakis's 111. Bush carried 40 of the 51 states that took part (including Washington, D.C.).
Winner
George H. W. Bush
426
Democratic
Michael Dukakis
111
official Electoral College count
RepublicanDemocraticNot a state yet / did not vote
Good to know
- Some electoral votes were split within states, cast by faithless electors or not counted, so the coloured states do not add up exactly to the official totals shown here. Each state is coloured by the party that won most of its electors.
States won in 1988
George H. W. Bush· Republican
40 statesCalifornia 47Texas 29Pennsylvania 25Illinois 24Ohio 23Florida 21Michigan 20New Jersey 16North Carolina 13Georgia 12Indiana 12Virginia 12Missouri 11Tennessee 11Louisiana 10Maryland 10Alabama 9Kentucky 9Colorado 8Connecticut 8Oklahoma 8South Carolina 8Arizona 7Kansas 7Mississippi 7Arkansas 6Nebraska 5New Mexico 5Utah 5Idaho 4Maine 4Montana 4Nevada 4New Hampshire 4Alaska 3Delaware 3North Dakota 3South Dakota 3Vermont 3Wyoming 3
Michael Dukakis· Democratic
11 statesElectoral College in 1988
51 states and Washington, D.C. held 538 electoral votes in 1988. The largest prize was California with 47 electoral votes.
Compare with every other election, see electoral votes by state today, or draw your own 2028 map.
Sources: Wikipedia (CC BY-SA 4.0): results by state, electors by state and year, and the 1988 election article.